4-6/x^2=-17

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Solution for 4-6/x^2=-17 equation:



4-6/x^2=-17
We move all terms to the left:
4-6/x^2-(-17)=0
Domain of the equation: x^2!=0
x^2!=0/
x^2!=√0
x!=0
x∈R
We add all the numbers together, and all the variables
-6/x^2+21=0
We multiply all the terms by the denominator
21*x^2-6=0
We add all the numbers together, and all the variables
21x^2-6=0
a = 21; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·21·(-6)
Δ = 504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{504}=\sqrt{36*14}=\sqrt{36}*\sqrt{14}=6\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{14}}{2*21}=\frac{0-6\sqrt{14}}{42} =-\frac{6\sqrt{14}}{42} =-\frac{\sqrt{14}}{7} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{14}}{2*21}=\frac{0+6\sqrt{14}}{42} =\frac{6\sqrt{14}}{42} =\frac{\sqrt{14}}{7} $

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